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LeetCode 1347 Minimum Number of Steps to Make Two Strings Anagram

LeetCode

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You are given two strings of the same length s and t. In one step you can choose any character of t and replace it with another character.

Return the minimum number of steps to make t an anagram of s.

An Anagram of a string is a string that contains the same characters with a different (or the same) ordering.

Example 1:

<pre>Input: s = "bab", t = "aba" Output: 1 Explanation: Replace the first 'a' in t with b, t = "bba" which is anagram of s. </pre>

Example 2:

<pre>Input: s = "leetcode", t = "practice" Output: 5 Explanation: Replace 'p', 'r', 'a', 'i' and 'c' from t with proper characters to make t anagram of s. </pre>

Example 3:

<pre>Input: s = "anagram", t = "mangaar" Output: 0 Explanation: "anagram" and "mangaar" are anagrams. </pre>

Constraints:

  • 1 <= s.length <= 5 * 10<sup>4</sup>
  • s.length == t.length
  • s and t consist of lowercase English letters only.

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题目大意:

通过替换字母使得两字符为同位词Anagram

解题思路:

统计某一个词的词频,遍历另一个单词,减去词频,若不够减(小于0),就加步数

解题步骤:

N/A

注意事项:

Python代码:

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def minSteps(self, s: str, t: str) -> int:
char_to_count_t = collections.Counter(t)
steps = 0
for char in s:
if char in char_to_count_t and char_to_count_t[char] > 0:
char_to_count_t[char] -= 1
else:
steps += 1
return steps

算法分析:

时间复杂度为O(n),空间复杂度O(n)

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