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Given an input string s, reverse the order of the words.
A word is defined as a sequence of non-space characters. The words in s will be separated by at least one space.
Return a string of the words in reverse order concatenated by a single space.
Note that s may contain leading or trailing spaces or multiple spaces between two words. The returned string should only have a single space separating the words. Do not include any extra spaces.
Example 1:
<pre>Input: s = "the sky is blue" Output: "blue is sky the" </pre>
Example 2:
<pre>Input: s = " hello world " Output: "world hello" Explanation: Your reversed string should not contain leading or trailing spaces. </pre>
Example 3:
<pre>Input: s = "a good example" Output: "example good a" Explanation: You need to reduce multiple spaces between two words to a single space in the reversed string. </pre>
Constraints:
1 <= s.length <= 10<sup>4</sup>scontains English letters (upper-case and lower-case), digits, and spaces' '.- There is at least one word in
s.
**Follow-up: **If the string data type is mutable in your language, can you solve it in-place with O(1) extra space?
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题目大意：
反转字符串中的单词顺序
解题思路：
N/A
解题步骤：
N/A
注意事项：
- word不能为空，单词之间可能含多个空格
Python代码：
1
2
3
4def reverseWords(self, s: str) -> str:
words = s.split(' ')
words_without_space = [word for word in words if word]
return ' '.join(words_without_space[::-1])
算法分析：
时间复杂度为O(n)，空间复杂度O(n)
